Question

Aflati media aritmetica a urmatoarelor grupe de numere: a) 0,(3), 1/5, 0,7, 1 intreg 1/2 b) 3/4, 0,(2), 0,1(6), 2 intregi 1/3, c) 1,7 , 0,(5) ,1,(1) ,1 intreg 1/10 , d) 3,5 , 0,4 ,1,(3) , 2 intregi 1/5 , e) 0,(7) ,3 intregi 1/3 , 0,25 ,1,1(6) va rogggggggg ajutatima!!!? Dau 11 puncte!!!

Answer 1

a) 0,(3) =3/9=1/3
 1/5
0,7 =7/10
 1 intreg 1/2  =3/2
(1/3+1/5+7/10+3/2)/4=[(10+6+21+45)/30]/4=82/120=41/60

b) 3/4
 0,(2) =2/9
 0,1(6)=(16-1)/90=15/90=1/6
 2 intregi 1/3=7/3
(3/4+2/9+1/6+7/3)/4=[(27+8+6+84)/36]/4=125/144

c) 1,7=17/10
 0,(5) =5/9
1,(1) =(11-1)/9=10/9
1 intreg 1/10=11/10
(17/10+5/9+10/9+11/10)/4=(28/10+15/9)/4= 
=[(252+150)/90]/4=402/360=67/60

d) 3,5 =35/10=7/2
0,4 =4/10=2/5
1,(3) =(13-1)/9=12/9=4/3
2 intregi 1/5 =11/5
(7/2+2/5+4/3+11/5)/4=(7/2+13/5+4/3)/4=[(105+78+40)/30]/4=223/120 


e) 0,(7) =7/9
3 intregi 1/3 =10/3
 0,25 =25/100=1/4
1,1(6) =(116-11)/90=105/90=21/18=7/6
(7/9+10/3+1/4+7/6)/4=[(28+120+9+42)/36]/4=199/144