Question

aflați media ponderata a nr 3/7 cu ponderile 2,respectiv 3, respectiv 7

Answer 1

$m_p=\frac{2\cdot\frac{3}{7}+3\cdot\frac{#}{7}+7\cdot\frac{3}{7}}{2+3+7}=\frac{3}{7}\cdot(2+3+7):(2+3+7)=3/7$

Answer 2

$mp= \frac{p1a1+p2a2+.....+pnan}{p1+p2+p3} = \frac{3/7*2+3/7*3+3/7*7}{2+3+7} = \\ \\ mp= \frac{6/7+9/7+3}{12} = \frac{15/7+3}{12}= \frac{36/7}{12} = \frac{3}{7}$