Question

aflati n :a)(2n-1)^3=125
b)n^3=2^3x3^6
c)(n-1)3=2^6x5^3
d)(4n-1)3=3^3x5)3
e)(2n+1)3=3^6x7^3

Answer 1

Rezolvarea este pe foaie!

Answer 2

a)(2n-1)^3=125
(2n-1)^3=5^3
2n-1=5
2n=5+1
2n=6
n=6:2
n=3

b)n^3=2^3x3^6
n^3=2^3× (3^2)^3
n^3=2^3×9^3
n^3=18^3
n=18

c)(n-1)^3=2^6x5^3
(n-1)^3=(2^2)^3× 5^3
(n-1)^3=4^3× 5^3
(n-1)^3=20^3
n-1=20
n=20+1
n=21


d)(4n-1)^3=3^3x5^3
(4n-1)^3=15^3
4n-1=15
4n=15+1
4n=16
n=16:4
n=4

e)(2n+1)^3=3^6x7^3
(2n+1)^3=(3^2)^3× 7^3
(2n+1)^3=9^3× 7^3
(2n+1)^3=63^3
2n+1=63
2n=63-1
2n=62
n=62:2
n=31