Question

Aflați n din: (4^n+3)^2×8^n=32×(8^14)^2​

Answer 1

Răspuns:

((4^(n+3))^2×8^n= etc

n∉N, ai gresit ceva in text

Explicație pas cu pas:

(2^(2n+6))²*(2³)^n=2^5*((2³)^14)²

2^(4n²+24n+36+3n)=2^(5+42*2)

2=2

4n²+27n+36=89

4n²+27n-53=0

n=(-27±√(27²+16*53))/8

n=(-27±3√1577)/8∉N pt ca 1577 nu e p.p , pt ca se termina in 7