Question

aflati necunoscuta in fiecare caz (x+3)x3+11=749,80+(x-10)=120,99x9+x=999+99-9

Answer 1

(x+3)x3+11=749
(x+3)x3=749-11
(x+3)x3=738
(x+3)=738:3
x+3=246
x=246-3
x=243

80+(x-10)=120
(x-10)=120-80
x-10=40
x=40+10
x=50

99x9+x=999+99-9
891+x=1.089
x=1.089-891
x=198