Question

aflati nr a,b,c , stiind ca : a+b= 117, a+c= 219 si b+c= 203

Answer 1

 a+b= 117, a+c= 218 si b+c= 203
a+b+a+c+b+c=117+218+203
2xa+2xb+2xc=538
2x(a+b+c)=538:2
a+b+c=269
117+c=269
c=269-117
c=152
b+152=203
b=203-152
b=51
a+51=117
a=117-51
a=66
Verific: 66+51+152=269 suma numerelor