Question

aflati nr. a daca 12+{2x[32+(a-24)x5]:4}x3=75

Answer 1

12 + { 2 × [ 32 + ( a - 24 ) × 5 ] : 4 } × 3 = 75

{ 2 × [ 32 + ( a - 24 ) × 5 ] : 4 } × 3 = 75 - 12

{ 2 × [ 32 + ( a - 24 ) × 5 ] : 4 } × 3 = 63

2 × [ 32 + ( a - 24 ) × 5 ] : 4 = 63 : 3

2 × [ 32 + ( a - 24 ) × 5 ] : 4 = 21

2 × [ 32 + ( a - 24 ) × 5 ] = 21 × 4

2 × [ 32 + ( a - 24 ) × 5 ] = 84

32 + ( a - 24 ) × 5 = 84 : 2

32 + ( a - 24 ) × 5 = 42

( a - 24 ) × 5 = 42 - 32

( a - 24 ) × 5 = 10

a - 24 = 10 : 5

a - 24 = 2

a = 2 + 24

a = 26

Answer 2

Explicație pas cu pas:

12+{2×[32+(a-24)×5]:4}×3=75

12+[2×(32+b×5):4]×3=75

12+[2×(32+c):4]×3=75

12+(2×d:4)×3=75

12+(e:4)×3=75

12+f×3=75

12+g=75

g=75-12

g=63

f×3=63

f=63:3

f=21

e:4=21

e=21×4

e=84

2×d=84

d=84:2

d=42

32+c=42

c=42-32

c=10

b×5=10

b=10:5

b=2

a-24=2

a=24+2

a=26