Question

Aflati nr naturale a b c a <b <c daca:5a+5b+5c=20;3a+6b+9c=42.​

Answer 1

Răspuns:

5a+5b+5c=20

5(a+b+c)=20

a+b+c=20:5=>a+b+c=4

a<b<c

a=0 , b=1, c=3

__________

3a+6b+9c=42

3(a+2b+3c)=42

a+2b+3c=14

a=1 , b=2 , c=3