Question

aflati nr naturale a,b,c daca a×(b-c)=56,c×(b-c)=24,2×a+3×c=23​

Answer 1

Explicație pas cu pas:

a(b - c) = 56

c(b - c) = 24

impartim prima ecuatie la a doua

a/c = 56/24 = 7/3

a = 7c/3

2a + 3c = 23

14c/3 + 9c/3 = 23

23c/3 = 23

c = 23*3/23 = 3

a = 7*3/3 = 7

7(b - 3) = 56

b - 3 = 56 : 7 = 8

b = 8 + 3 = 11