Question

aflati nr. naturale a,b si c care verifica simultan egalitatile a+b=24 , b+c=18 , c+a=26

Answer 1

a + b = 24
b + c = 18
a + c = 26
________ (+)
a + b + b + c + a + c = 24 + 18 + 26 => 2a + 2b + 2c = 42 + 26 => 2(a + b + c) = 68 => a + b + c = 34

a + b + c = 34
a + b = 24
_______ (-)
a + b + c - a - b = 34 -24 => c = 10

a + b + c = 34
b + c = 18
_______ (-)
a + b + c - b - c = 34 - 18 => a = 16

b + c = 18 => b + 10 = 18 => b = 18-10 => b = 8


a = 16, b = 8, c = 10

Answer 2

a+b+c+a = 26 + 24
2a +18 =50 
2a = 50-18 
2a= 32 
a= 32 : 2 
a=16

a+b = 24 
18 + b= 24 
b= 24 - 18 
b= 6 

b+ c = 18 
6+c =18 
c=18-6
c=12  

c+a = 26 
12 + 16 = 26 

  NU ESTE CORECT ! scuza-ma :(