Question

aflati nr naturale nenule care impartite la 6 dau catul egal cu restul

Answer 1

Din regula impartirii D:6=C+R C=R R<6 C=R<6 Daca C=R=1 => D=6*1+1=7 C=R=2 =>D=6*2+2=14 C=R=3 => D=6*3+3=21 C=R=4 => D=6*4+4=28 C=R=5 => D=6*5+5=35

Answer 2

7:6=1 rest 1=> 7=6*1+1=>6+1=7
14:6=2 rest 2 =>14=6*2+2=> 12+2=14
21:6=3 rest 3 =>21=6*3+3=> 18+3=21
28:6=4 rest 4 =>28= 6*4+4=> 24+4=28
35:6=5 rest 5=> 35=6*5+5=>30+5=35