Question

Aflați nr necunoscut:

42-{3×[19-2×(13-36:a)]-10}=1​

Answer 1

Răspuns:

42-{3×[19-2×(13-36:a)]-10}=1

3×[19-2×(13-36:a)]-10=42-1

3×[19-2×(13-36:a)]-10=41

3×[19-2×(13-36:a)]=41+10

3×[19-2×(13-36:a)]=51

19-2×(13-36:a)=51:3

19-2×(13-36:a)=17

2×(13-36:a)=19-17

2×(13-36:a)=2

13-36:a=2:2

13-36:a=1

36:a=13-1

36:a=12

a=36:12

a=3