Question

Aflati nr X pt care are loc egalitatea:{1,2}^10*{1,2}^20*{1,2}^30*...*{1,2}^100={6supra5}^0,4*X

Answer 1

1,2^(10+20+....+100)=1,2^(0,4x)
10+20+...+100=0,4x
100+200+...+1000=4x
100(1+2+...+10)=4x
25(1+2+....+10)=x
x=25*10*11/2
x=25*5*11
x=125*11
x=1375