Question

Aflați nr x, y, z, t stiind ca sunt invers proportionale cu 1/6, 1/24, 1/30, 1/55, iar x+y+z+t=125.

Answer 1

x+y+z+t =125
x/6 =y/24 =z/30 =t/55

x/6 +y/24+z/30+t/55 =x+y+z+t /6+24+30+55 =125/115 =25/23

x/6 =25/23    x =6*25/23 =150/23 =6.52
y/24 =25/23     y =24*25/23 =600/23 =26.09
z/30 =25/23      z =30*25/23 =750/23 =32.61
t /55 =25/23      t =55*25/23 =59.78
v ;   6.52+26.09+32.61+59.78 =125