Question

Aflati numarul a daca:
b.) 64-120:(30×2:10)-a=40
c.) 460-4×[a×(30-20:5:4)]=58
n.) 135+5000:(1455-455)+a×(40+4)=272
o.) 832:a+[40+8×(100:5-90:5)]×10=592
pls dau coroana ​

Answer 1

Răspuns:

b) 64-120÷6-a=40

=64-20-a=40

=44-a=40

=-a=40-44

=-a=-4

a=4

c) 460-4×[a×(30-1)]=58

=460-4×(a×29)=58

=460-4×(29a)=58

=460-4×29a=58

=460-116a=58

=-116a=58-460

=-116a=-402

a=

$\frac{201}{58}$

n)135+5000÷1000+a×44=272

=135+5+44a=272

=140+44a=272

=44a=272-140

=44a=132

=a=3

o) 832÷a+[40+8×(100÷5-90÷5)]×10=592, a= =taiat 0

=

$\frac{832}{a}$

+[40+8×(20-18)]×10=592

=

$\frac{832}{a}$

+(40+8×2)×10=592

=

$\frac{832}{a}$

+(40+16)×10=592

=

$\frac{832}{a}$

+56×10=592

=

$\frac{832}{a}$

+560=592

=

$\frac{832}{a}$

=592-560

=

$\frac{832}{a}$

=32

=832=32a

32a=832

a=26, a= =taiat 0

a=26