Question

aflati numarul intreg n care verifica inegalitatile:
3 pe 4 mai mic ca n pe 6 mai mic ca 8 pe 9.

Answer 1

Din $\frac{3}{4} < \frac{n}{6} =>n> \frac{3*6}{4} = \frac{18}{4} = \frac{9}{2}$
Din $\frac{n}{6} < \frac{8}{9} => n< \frac{6*8}{9} = \frac{48}{9} = \frac{16}{3}$
Avem: $\frac{9}{2}$<n< $\frac{16}{3}$ . n∈Z => n=5.