Question

Aflati numarul natural x, daca: {181+[98+(169: x+ 35):4]: 10}:16=12
Va rog sa ma ajutati!!!

Answer 1

{181+[98+(169: x+ 35):4]: 10}:16=12

181+[98+(169: x+ 35):4]: 10=12×16

181+[98+(169: x+ 35):4]: 10=192

[98+(169: x+ 35):4]: 10=192-181

[98+(169: x+ 35):4]: 10=11

98+(169: x+ 35):4=11×10

98+(169: x+ 35):4=110

(169: x+ 35):4=110-98

(169: x+ 35):4=12

169: x+ 35=12×4

169: x+ 35=48

169: x=48-35

169: x=13

x=169:13

x=13

Answer 2

{...}=16*12
{...}=192
181+[...]:10=192
[...]:10=11
[...]=110
98+(..):4=110
(...):4=12
(...)=48
169:x+35=48
169:x=13
169=13x
13x=169
x=169:13
x=13