Question

aflați numărul natural x din egalitatea: 2+2x{4+4x[5+5:(15-x)]}=58
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Answer 1

2+2x{4+4x[5+5:(15-x)]}=58

2+2x{4+4x[5+5:15-5:x]}=

=2+2x{4+4x[5+1/3-5/x]}=

=2+2x(4+4x×5+4x×1/3-4x×5/x)=

=2+2x(4+20x+4x/3-20)=

=2+2x(20x+4x/3-16)=

=2+2x×20x+4x/3×2x-32x=

=2+40x×x+8x×x/3-32x=

= 6+120xx+8xx-96x/3=58

=> 6+120xx+8xx-96x= 174

=> 128xx-96x=168

x(128x-96)=168

x=168/128x-96

x=84/64x-48

x=42/32x-24

x=21/16x-12

x=21(16x+12)/16×16xx-144