Question

aflati numarul necunoscut 3x2xm =9x6 32/y=36/9 3x3xn=6x6 qx5<54 z/7<8

Answer 1

3 x 2 x m = 9 x 6
6 x m = 54
m = 54 : 6
m = 9

32 : y = 36 : 9
32 : y = 4
y = 32 : 4
y = 8

3 x 3 x n = 6 x 6
9 x n = 36
n = 36 : 9
n = 4

q x 5 < 54
q = 1 , 2, 3, 4, 5, 6, 7, 8, 9, 10
1 x 5 = 5 < 54
2 x 5 = 10 < 54
.................
10 x 5 = 50 < 54

z : 7 < 8
z = 7 , 14 , 21 , 28 , 35, 42,49
7 : 7 = 1 < 8
14 : 7 = 2 < 8
............
49 : 7 = 7 < 8

Answer 2

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