Question

Aflati numarul x din egalitatea 65-[2x+[(x:4+32)]:4+58]:3}:7=48
Va rog frumos cat de repede se poate sa ma ajutati

Answer 1

65-{2x+[ (x:4+32):4+58]:3}:7=48
-{2x+[ (x:4+32):4+58]:3}:7= 48-65
-{2x+[ (x:4+32):4+58]:3}:7= -17
2x+[ (x:4+32):4+58]:3=17*7
2x+[ (x:4+32):4+58]:3=119
2x+(x/16+8+58):3=119
2x+(x/16+66):3=119
2x+x/48+22=119
2x+x/48=119-22
2x+x/48= 97
2*48+x=97*48
97x=97*48
x=48