Question

aflati numarul x,y,z direct proportionale cu 5,6,10 daca 2x+3y=128 

Answer 1

{x, y, z} d.p. {5,6,10) => x=5k y=6k z=10k

2x + 3y= 128

10k+18k=128 -> 28k=128

K=4,5

X=4,5*5=22,5

Y=4,5*6=27

Z=4,5*10=45