Question

aflati numarul x y z stiind ca x+y z+z z+× sint direct proportionale cu nr. 6,9,12 si k x+y+z=27
clasa6

Answer 1

x+y+z=27   x/6+y/9+z/12

Answer 2

x+y=6k
y+z=9k
z+x=12k
x+y+y+z+z+x=27k
2(x+y+z)=27k
x+y+z=27  ⇒ k=2
x+y=6k=12   ⇒x=12-y ⇒x= 12-18-z⇒ x=z-6
y+z=9k=18   ⇒y=18-z
z+x=12k=24  ⇒ z+z-6=24 ⇒ z=(24+6)/2 ⇒ z=15
x=24-15=9
y=18-15=3