Question

aflati numere a,b,c invers proportionale cu numerele 3,8 12 ca 4a+2b-3c=64

Answer 1

3a=8b=12c=d
a=1/3d
b=1/8d
c=1/12d
4/3d+2/8d-3/12d=64
32/24d+6/24d-1/4d=64
38/24d-6/24d=64
32/24d=64
d=48
a=16
b=6
c=4

Answer 2

3a = 8b = 12c -> a=4c ; b=1,5c ; 4a+2b-3c= 16c + 3c - 3c= 16 c= 64 -> c= 4; a=16; b=6