Question

aflati numerele a si b din egalitatile;
[(a+116:2)*3+4]*11=1991

Answer 1

(a+58)x3+4=1991:11 (a+58)X3+4=181. (a+58)x3=181-4. (a+58)X3=177 a+58=177:3 a+58=59 a=59-58 a=1

Answer 2

$(a+58)*3+4=1991:11 \\ (a+58)*3=181-4 \\ a+58=177:3 \\ a=59-58 \\ a=1$