Question

Aflati numerele a si b din egalitatile:
[(a+116:2)x3+4]x11=1991
(b:11minus4):3minus110:2=4
voi da coroana maine incep la 8:00 si este urgentttttt!!!!!!!!!!!!!

Answer 1

[(a+58)x3+4]x11=1991
(a+58)x3+4=1991:11
(a+58)x3+4=181
(a+58)x3=181-4
(a+58)x3=177
a+58=177:3
a+58=59
a=59-58
a=1
(b:11-4):3-110:2=4
(b:11-4):3-110=8
(b:11-4):3=8+110
(b:11-4):3=118
b:11-4=118:3
b:11-4=39.3
b:11=35.3
b=35.3x11
b=388.3
iti da cu virgula. ori e gresit exercitiul ori asa trebuie sa faci

Answer 2

a)

{(a+16:2)*3+4]*11=1991
((a+116:2)*3+4)*11-(1991)=0
((((a+58)*3)+)*11-1991=0
((3*(a+58)+4)*11)-1991=0
11*(3a+178)-1991=0
33a-33=33*(a-1)
33=0
a-1=0
a=1


b) 

(b:11-4):3-110:2=4
(b:11-4):3-110:2-(4)=0
((b:11-4):3-55)-4=0
4=4/1=4*11/11
b-(4*11)/11=b-44/11
((b-44)/11:3-55)-4=0
((b-44)/33-55)-4=0
55=55/1=55*33/33
(b-4)-(55*33)/33=b-1859/33
(b-1859)/33-4=0
4=4/1=4*33/33
(b-1859)-(4*33)/33=b-1991/33
b-1991/33=0
b-1991/33 *33=0*33
b-1991=0
b=1991

a=1
b=1991