Question

Aflati numerele a și b din egalitatile :
a) [(a+116:2) × 3 + 4] × 11 = 1991
b) (b : 11 - 4) : 3 -110 :2= 4
Cine mă ajuta dau coroana

Answer 1

a) (a+116:2) × 3 + 4 = 1991:11
     (a+116:2) × 3 = 181 - 4
     a + 58 = 177:3
    a = 59 - 58 = 1

b) (b : 11 - 4) : 3 - 55 = 4
     (b : 11 - 4) : 3 = 4 + 55 = 59
     b:11 - 4 = 59 * 3
     b:11 = 177 + 4 = 181
     b = 11*181 = 1991

Answer 2

a)
[(a+116÷2)×3+4]×11=1991 | ÷11
(a+116÷2)×3+4=181 | -4
(a+116÷2)×3=177 | ÷3
a+116÷2=59
a+58=59
a=59-58
a=1

b)
(b÷11-4)÷3-110÷2=4
(b÷11-4)÷3-55=4 | +55
(b÷11-4)÷3=59 | ×3
b÷11-4=177 | +4
b÷11=181 | ×11
b=1991