Question

aflati numerele a si b din relatiile de mai jos:
{[360:(240-a)]+290}:50=7
{[(b+400)×3]+33}:60=21

Answer 1

{[360:(240-a)]+290}:50=7
[360:(240-a)]+290=7x50
[360:(240-a)]+290=350
360:(240-a)=350-290
360:(240-a)=60
240-a=360:60
240-a=6
a=240-6
a=234

{[(b+400)x3]+33}:60=21
[(b+400)x3]+33=21x60
[(b+400)x3]+33=1260
(b+400)x3=1260-33
(b+400)x3=1227
b+400=1227:3
b+400=409
b=409-400
b=9