Question

aflati numerele ar caror suma este 130 si care sint invers proportionale cu numerele 2 3 si4..

Answer 1

$a+b+c=130$
$a= \frac{1}{2}$
$b= \frac{1}{3}$
$c= \frac{1}{4}$
$2a=3b=4c$
$b= \frac{2a}{3}$
$c= \frac{2a}{4} = \frac{a}{2}$
$a+ \frac{2a}{3} + \frac{a}{2} =130$
$\frac{6a+4a+3a}{6} =130$
$13a=6*130$    ⇒   $a= \frac{6*130}{13} =6*10$
$a=60$
$b= \frac{2a}{3}$    ⇒   $b= \frac{2*60}{3} = \frac{120}{3}$
$b=40$
$c= \frac{a}{2}$    ⇒   $c= \frac{60}{2}$
$c=30$