Question

Aflati numerele care:
a). au suma 1174, catul 13 si restul 12;
b). au diferenta 548, catul 23 si restul 21.

Answer 1

a+b=1174
a÷b=13 rest 12
a=13b+12
13b+12+b=1174
14b=1174-12
14b=1162
b=1162÷14
b=83
a+83=1174
a=1174-83
a=1091
R: a=1091 ; b=83
verificare
1091+83=1174

b)
a-b=548
a÷b=23 rest 21
a=23b+21
23b+21-b=548
22b=548-21
22b=527
b=527÷22
b=23,95
a-23,95=548
a=548+23,95
a=571,95
verificare
571,95-23,95=548

SAU ( daca restul era 20 )
a-b=548
a÷b=23 rest 20
a=23b+20
23b+20-b=548
22b=548-20
22b=528
b=528÷22
b=24
a-24=548
a=548+24
a=572
verificare
572-24=548
572÷24=23 rest 20
572=23×24+20
572=552+20
572=572