Question

aflati numerele naturale care impartite la 9 dau catul si restul doua nr naturale consecutive (catul mai mic decat restul)

Answer 1

N={0*9+1=1; 1*9+2=11; 2*9+3=21; 3*9+4=31; 4*9+5=41; 5*9+6=51; 6*9+7=61; 7*9+8=71}