Question

aflati numerele naturale care impartite la 9 dau catul si restul doua numere naturale consecutive(catul mai mic deecat restul)

Answer 1

x:9=c₁ rest c₁+1
R<I
C<R

C<R<I

x=M₉+ c₁+1

x=M₉+1

1)C=1=>R=0
x=9*1+0
x=9+0
x=9

2)C=2=>R=1

x=9*2+1
x=18+1
x=19

3)C=3=>R=2

x=9*3+2
x=27+2
x=29

4)C=4=>R=3

x=9*4+3
x=36+3
x=39

5)C=5=>R=4

x=9*5+4
x=45+4
x=49

6)C=6=>R=5

x=9*6+5
x=54+5
x=59

7)C=7=>R=6

x=9*7+6
x=63+6
x=69

8)C=8=>R=7

x=9*8+7
x=72+7
x=79