Question

Aflati numerele naturale x si y astfel incat urmatoarele fractii sa formeze un sir de fractii echivalente :
$\frac{24}{36}$
$\frac{12}{x+2}$
$\frac{y+1}{6}$

Answer 1

$\frac{24}{36}= \frac{12}{x+2} = \frac{y+1}{6}$
$\frac{24}{36}= \frac{12}{x+2} <=> \frac{12}{18}= \frac{12}{x+2} =>x+2=18=>x=16. \\ \frac{24}{36}= \frac{y+1}{6} <=> \frac{4}{6}= \frac{y+1}{6}=>4=y+1=>y=3.$

Answer 2

24/36 = 12/18 = > x + 2 = 18 => x =16
24/36 = 4/6 => y + 1 = 4 => y = 3