Question

Aflati numerele naturale x, stiind ca :(2^3*3)^2+5^2*x <sau =606

Answer 1

$( 2^{3} *3) ^{2} +5 ^{2} *x\leq 606$
$( 24) ^{2} +25 *x\leq 606$
$576 +25 *x\leq 606$
$25 *x\leq 606-576$
$25 *x\leq 30$
$x\leq \frac{30}{25}$
$x\leq \frac{6}{5}$