Question

Aflati numerele reale a si b , pentru care a la a 2 + b la a 2  - 2 a - 6b +10 = 0 

Answer 1

[tex]a^2+b^2-2a-6b+10=0\\ a^2-2a+1^2+b^2-2\cdot b\cdot 3+3^2=0\\ (a-1)^2+(b-3)^2=0\\ \left \{ {{a-1=0=>a=1} \atop {b-3=0=>b=3}} \right. [/tex]