Question

Aflati numerele x,y,z invers proportionale cu 0,(3); 0,5; 0,25 care sunt in relatia 18x+6y-15z=150

Answer 1

0,(3)=3/9=1/3
0,5=5/10=1/2
0,25=25/100=1/4
{x,y,z}ip{1/3,1/2,1/4}
x/3=y/2=z/4=k
x=3k
y=2k
z=4k
inlocuim in relatia 18x+6y-15z=150
18·3k+6·2k-15·4k=150
54k+12k-60k=150
6k=150
k=150/6=25
k=25
x=3k=3·25
x=75
y=2k=2·25
y=50
z=4k=4·25
z=100