Question

aflati numerele x,y,z stiind ca ele sunt direct proportionale cu : 3;4;7 si x+2y+3z=64​

Answer 1

Răspuns:

Explicație pas cu pas:

x/3 = y/4 = z/7 = k

x = 3k

y = 4k

z = 7k

x + 2y + 3z = 64

3k + 8k + 21k = 64

32k = 64

k = 64 : 32 = 2

x = 3*2 = 6

y = 4*2 = 8

z = 7*2 = 14

Answer 2

x+2y+3z=64

x/3=y/4=z/7=k

x=3k

y=4k

z=7k

3k+2×4k+3×7k=64

3k+8k+21k=64

32k=64

k=64:32

k=2

x=3×2

x=6

y=4×2

y=8

z=7×2

z=14