Question

Aflati numerele x,y,z stiind ca x/2=y/5 = z/8 si 2x+ y + z = 68 .

Answer 1

x/2=y/5 = z/8 si 2x+ y + z = 68 .

x/2=y/5 = z/8=k

x=2k  ;  y=5k ;    z= 8k

2*2k+5k+8k=68

17k=68
k=4
deci numerele sunt

x=2k=8
y=5k=20
z=8k=32
verificare
2x+y+z=68
16+20+32=68
68=68
deci x=8, y=20,  z=32

Answer 2

2x2x+8x+5x=68
4x+8x+5x=68
x=68:17
x=4