Question

Aflati partea imaginara a numarului complex z=$\frac{6}{1+i}$ .

Answer 1

z=6/(1+i)=>amplific cu 1-i
z=6(1-i)/(1-i^2)
i^2=-1
z=6 (1-i)/(1+1)
z=6(1-i)/2
z=3 (1-i)
z=3-3i
Deci Im (z)=-3