Question

aflati partea intreaga din radical din n^2+n

Answer 1

   
[tex] \sqrt{n^2+n} = \sqrt{n(n+1)} \ \textless \ \sqrt{(n+1)(n+1)} =\sqrt{(n+1)^2} \\ \\ \sqrt{n^2+n} \ \textgreater \ \sqrt{n^2} \\ \\ \Longrightarrow ~~~[\sqrt{n^2+n}] = \sqrt{n^2} = \boxed{n}[/tex]