Question

Aflati patru numere naturale consecutive stiind ca impartind suma lor la 17 obtinem catul 12 si restul 6

Answer 1

(a+a+1+a+2+a+3):17= 12, rest 6
4a+6= 12*17+6
4a+6= 204+6
4a+6= 210
4a= 210-6
4a= 204
a= 204:4
a= 51
nr sunt: 51,52,53,54

Answer 2

x:17=12r6
x=12*17+6
x=210
a+b+c+d=210
a+a+1+a+2+a+3=210
a=210-6
a=51 , b=52, c=53, d=54