Question

Aflati pe x din 10:x+2x=9

Answer 1

[tex]2 x^{2} -4x-5x+10=0 [/tex]
$2x^{2} -9x+10=0$
2x(x-2)-5(x-2)=0
(2x-5)(x-2)=0
2x-5=0
2x=5
$x=\frac{5}{2}$
x-2=0
x=2