Question

aflati perechiile de numere naturale in cazurile
(a+1) ×(b-2)=10

Answer 1

(a+1)(b-2)=1*10

a=0;b=12

(a+1)(b-2)=10*1

a=9;b=3

(a+1)(b-2)=2*5

a=1;b=7

(a+1)(b-2)=5*2

a=4;b=4