Question

Aflati perimetrul si aria unui dreptunghi cu L=12 hm si l=2 supra 3 din L!Va rog sa ma ajutati.Dau coroana!

Answer 1

$L=12hm \\ l= \frac{2}{3}*L \\ l= \frac{2}{3} *12 \\ l= \frac{24}{3} \\ l=8hm \\ P _{dr.} =2*(L+l) \\ P _{dr.}=2*( 12+8) \\ P _{dr.}=2*20 \\ P _{dr.}=40hm \\ \\ A _{dr.}=L*l \\ A _{dr.}=12*8 \\ A _{dr.}=96hm^2$

Answer 2

L=12hm
l=2/3* L
P=?
A=?

L=12hm
l=2/3*12hm
l=2*12/3 hm
l=24/3 hm
l=8 (hm latimea)
P=(L+l)*2
P=(12hm+8hm)*2
P=20hm*2
P=40(hm perimetrul)
A=L*l
A=12hm*8hm
A=96hm²(aria)