Question

Aflati primele 4 numare care impartite la 8/12/15 dau restul 3
Repedee!!

Answer 1

d:8=1 rest 3
d=1x8+3=8+3=11(deimpartitul)
d:8=2 rest 3
d=19
d:8=3 rest 3
d=3x8+3
d=25
d:8=4 rest 3
d=4x8+3
d=35
asadar numerele care se impart la 8 si au restul 3 sunt: 11, 19, 25, 35

d:12=1 rest 3
d=1x12+3
d=15(deimpartitul)
d:12=2 rest 3
d=2x12+3
d=27
d:12=3 rest 3
d=3x12+3
d=39
d:12=4 rest 3
d=4x12+3
d=51

d:15=1 rest 3
d=1x15+3
d=18
d:15=2 rest 3
d=2x15+3
d=33
d:15=3 rest 3
d=3x15+3
d=48