Question

Aflați rădăcina pătrată a numărului natural n în următoarele cazuri:

a)

n=24309+486:√324

b)

n=33822+748:√484

c)

n=101127-√2601:√289

d)

n=111561-√9025:√361

Trebuie cu rezolvare!

Answer 1

   
$\sqrt{n}=\sqrt{24309+486:\sqrt{324}}=\\ =\sqrt{24309+486:18}=\sqrt{24309+27}=\sqrt{24336}=\boxed{\bf 156}\\\\ b)\\ \sqrt{n}=\sqrt{33822+748:\sqrt{484}}=\\ =\sqrt{33822+748:22}=\sqrt{33822+34}=\sqrt{33856}=\boxed{\bf 184}\\\\ c)\\ \sqrt{n}=\sqrt{101127-\sqrt{2601}:\sqrt{289}}=\\ =\sqrt{101127-51:17}=\sqrt{101127-3}=\sqrt{101124}=\boxed{\bf 318}\\\\ d)\\ \sqrtn}=\sqrt{111561-\sqrt{9025}:\sqrt{361}}=\\ =\sqrt{111561-95:19}=\sqrt{111561-5}=\sqrt{111556}=\boxed{\bf 334}$