Question

aflati rezultatul calcului: 2^21:[(3^3×5:15+7^0)^5:10^3-6^2]^3+79=
ajutorrr

Answer 1

2^21:[(3^3×5:15+7^0)^5:10^3-6^2]^3+79=
=2^21:[(3^2×15:15+1)^5:10^3-6^2]^3+79=
=2^21:[(3^2+1)^5:10^3-6^2]^3+79=
=2^21:(10^5:10^3-6^2)^3+79=
=2^21:(10^2-6^2)^3+79=
=2^21:(64)^3+79=
=2^21:(2^6)^3+79=
=2^3+79=
=8+79=87

Answer 2

2^21:[(3^3•5:15+7^0)^5:10^3-6^2]^3+79
2^21:[(27•5:15+1)^5:1000-36]^3+79
2^21:[(135:15+1)^5:1000-36]^3+79
2^21:[(9+1)^5:1000-36]^3+79
2^21:(10^5:1000-36)^3+79
2^21:(100000:1000-36)^3+79
2^21:(100-36)^3+79
2^21:64^3+79
2097152:262144+79
8+79
87