Question

Aflati suma numerelor necunoscute din egalitatile

a) (253+a):10-153=147
b) (b-35)×8-550:5=123-(7×9+2×5)
c) c+c×40:(23+17)+c×155:5-30)-c×(4000:10:4-9×11)=2018

Answer 1

Răspuns:

Explicație pas cu pas:

a)

( 253 + a ) : 10 - 153 = 147

( 253 + a ) : 10 = 147 + 153

( 253 + a ) : 10 = 300

253 + a = 300 × 10

253 + a = 3 000

a = 3 000 - 253

a = 2 747

____________________

b)

( b - 35 ) × 8 - 550 : 5 = 123 - ( 7 × 9 + 2 × 5 )

( b - 35 ) × 8 - 110 = 123 - ( 63 + 10 )

( b - 35 ) × 8 - 110 = 123 - 73

( b - 35 ) × 8 - 110 = 50

( b - 35 ) × 8 = 50 + 110

( b - 35 ) × 8 = 160

b - 35 = 160 : 8

b - 35 = 20

b = 20 + 35

b = 55

____________________

c + c × 40 : 40 + c × ( 155 : 5 - 30 ) - c × ( 4 000 : 10 : 4 - 9 × 11 ) = 2 018

c + c + c × ( 31 - 30 ) - c × ( 100 - 99 ) = 2018

2 × c + c × 1 - c × 1 = 2018

2 × c = 2018

c = 2018 : 2

c = 1009

Answer 2

Am putut sa l aflu doar pe a si b pe c nu am putut