Question

aflati suma primelor 200 de numere naturale pare nenule

Answer 1

2+4+6+8+...+200
=[200(200+201)]/2
=(200×401)/2
=80200÷2
=40100

Answer 2

2+4+6+ ... + 200 = 2×( 1+2+3+ ... + 100) =
                            = 2×(100×101 : 2) = 100×101 = 10100 ;