Question

aflati suma tuturor numerelor naturale care impartite la 6 dau catul egal cu restul.

Answer 1

$D:6=C \ , \ R \ \ \ \ I\ \textgreater \ R \ , \ C \neq 0 \ \ \ (N)\\\\ I=6 \Longrightarrow R \in \{0;1;2;3;4;5\} \\\\ \underline{R=C= \{1;2;3;4;5\}} \\\\\\ D=6 \cdot C+ R \\\\ Pentru: \\\\ C=R=1 \to D_1=6*1+1=6+1 \to 7 \\\\ C=R=2 \to D_2=6*2+2=12+2 \to 14 \\\\ C=R=3 \to D_3=6*3+3=18+3 \to 21 \\\\ C=R=4 \to D_4=6*4+4=24+4 \to 28 \\\\ C=R=5 \to D_5=6*5+5=30+5 \to 35 \\\\\\ \hbox{Suma numerelor este:} \\\\ S=7+14+21+28+35 \\\\ \boxed{S \to 105}$