Question

aflati suma tuturor numerelor naturale care impartite la 7 dau catul 10

Answer 1

☆Răspuns: Suma = 511

☆Rezolvare:

•Aflăm numerele:

a ÷ 7 = 10

a = 7 × 10

a = 70

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b ÷ 7 = 10 rest 1

b = 7 × 10 + 1

b = 70 + 1

b = 71

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c ÷ 7 = 10 rest 2

c = 7 × 10 + 2

c = 70 + 2

c = 72

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d ÷ 7 = 10 rest 3

d = 7 × 10 + 3

d = 70 + 3

d = 73

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e ÷ 7 = 10 rest 4

e = 7 × 10 + 4

e = 70 + 4

e = 74

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f ÷ 7 = 10 rest 5

f = 7 × 10 + 5

f = 70 + 5

f = 75

-----------------------------------

g ÷ 7 = 10 rest 6

g = 7 × 10 + 6

g = 70 + 6

g = 76

•Aflăm suma numerelor :

70 + 71 + 72 + 73 + 74 + 75 + 76 = 511

☆Sper că te-am ajutat! Succes! :))